Talk:HP Smart Pin
smart pin notes and comments
HP PN# 482133-001
outer layer go to GND, mid layer go to VOUT, inner layer to ID.
TRIVIAL NOTE: Seems like the ID pin is used for some kind of communication between adapter and notebook.. It transmit a signal at lower tension so that notebook recognize the adapter as an original HP product!
This pin is used to identify that a HP adapter is being used and not a 3rd party one.It is wired to some sort of DC signal input on the motherboard.
Ground is on the outside as normal, +19 volts on the inner ring and the center is where the "smart-pin" goes. If you only apply power to the inner & outer rings the laptop will not power up. You need to apply +19 to the center pin as well. According to HP "The Smart technology signals the power rating and if maximum rating of the adapter is reached, the notebook will reduce its power consumption". I do not know how the signaling works as I do not have a "smart-pin" adapter.
If you want to bypass it you can simply add a resistor between voltage and the smart pin. 430k will be good. The original resistor on HP power supplies is 390K.
If the voltage of the center pin differs from 5V, the processor will run on 10% of its nominal performance. Check the connection of the center pin. If it shorted to the main supply line, it will behaves the same. Under load, you should measure 5V on the center, and 20V on the main supply (center ring) pin.
This is your way if you wish to use replacement charger: Make voltage divider like mentioned before and aim getting 5,75V out to middle pin. You can get it work by using 10K and 4,7K resistors. This results 6,2V, which is close enough to fool your HP.
L2-cache got disabled when the middle-pin doesn’t supply at least 4V. the result is, that the system behaves just normal in bios, grub or memtest, but gets slow after leaving real-mode.
that the 65W charger output something around 2.5 to 3v on the centre pin, and the 90W mains charger some 5-7v, but the relationship between control voltage and current drawn was not obvious. However, one thing was clear: less than 5v on the control pin causes the laptop to be in "don't charge" mode: the word "charging" disappears, and the batter icon loses the "lightning bolt".
The 65W charger (in charge mode) starts with about 5.2v on the centre pin, then at some point it jumps to about 6.8v and seems to stay there. It draws about 3.3A.
Smart pin voltage-to-capacity correlation for laptop power supplies
The "smart" pin (center pin) on laptop power supply connectors is used for the purpose of the computer being able to determine the amperage (or wattage, if you prefer) of the 18.5 volt power supply that is plugged in to it, so it does not exceed it's capacity, especially when the computer is running AND charging the battery (or batteries) at the same time. I found a thread relating to this (topic#137840), but it is closed, and it did NOT provide the answer that I was looking for, anyways.
I believe that the pin voltage will vary between around 5-6 volts to maybe 10-12 volts. The higher the voltage, the more current (amps) the PS can deliver. If the pin voltage is outside of this range, or the center wire is broken off at the connector, the laptop will not run off of it (at least for HP/compaq laptops). I run into the broken off center conductor wire scenario regularly. I suppose that is the one that always breaks first because it is the thinnest of the wires going to the plug, from the PS.
I use one of those 6.7 amp brick-sized power supplies on my compaq 6715b, because it has a secondary battery attached to it (underneath). But the interesting thing is that I had the PS connected to a Dell laptop once, and it would run the computer, but refused to charge the battery. When the PS was plugged into it, a message would come up on the screen stating that the type of the PS could not be determined.
Assuming that ALL brands of laptops now use the same type of power connector, is there any sort of "standard" among manufacturers that correlates center-pin voltage with PS capacity, or is it wide open to whatever they decide?
If there is a standard, could someone please provide me with the link to some sort of "correlation table" showing center pin voltage vs. PS capacity?
I recently got myself a HP Thin Client which I want to use for OpenWrt and bridge it to my ISP modem. I actually have this exact setup running right now, only the PC being used for the router is just overkill for the job, hence the thin client. Tbh, the thin client is also seriously more powerful than it needs to be for a home router but meh. Anyway, the thin client uses a weird power connector (it came without a PSU) which I later found was a "Smart Pin" connector used mainly on laptops. It has an outer ring and a central pin. So I ordered a cable with this connector on the end from e-bay, the outside of the outer ring is ground, the inside of the outering is +19.5v and the centre pin is the "Smart Pin". I have tonnes of laptop power supplies so I figured I'll just modify one with this cable. If I just connect +ve and -ve and leave the smart pin unconnected, the thin client doesn't power on. I tried doing some Googling and found a bunch of conflicting information ranging from 1-Wire ID to transistors/mosfets and the like. But the one that made sense was that the centre pin was just the middle of a resistor divider. So, I tested between ground and the smart pin on the thin client. It reads 73K ohms steady. So I'm thinking it's probably a low precision 75K resistor in the thin client. I'm assuming that different power supplies have different resistors between +ve and the smart pin, when plugged in the resistor in the PSU and the resistor in the device (laptop/thin client, whatever) form a resistor divider between +ve and ground, the device is then able to read the voltage at the middle of the divider to ascertain the PSU's current capacity.
That being the case, which I'm 99% sure it is as putting a 100K resistor between +ve and the smart pin allows the thin client to start up. But, it would be nice to figure out the correct resistor value I need for the PSU's current/power. It's a 19.5V 6.7A 130W PSU. I tried Googling for some kind of chart that lists the voltages at the smart pin. It may not be as simple as that though, as some devices apparently have different resistors to ground, so the voltage at the smart pin would be different for the same PSU, in which case the chart would need to list the resistor values required (as the device would know the voltages)
Table of Contents
How do I bypass HP Smart PIN?
If you want to bypass it you can simply add a resistor between voltage and the smart pin. 430k will be good. The original resistor on HP power supplies is 390K. If the voltage of the center pin differs from 5V, the processor will run on 10% of its nominal performance.
How do I turn off HP Smart notifications?
Open the Devices and Printers folder, right-click the HP UPD, and then select Properties. Click the Device Settings tab. In the Installable Options section, set Printer Status Notification to either Enable or Disable. Click OK.
Can I turn off HP Support Assistant?
In Windows, search for and open Task Scheduler. Double-click Hewlett-Packard, then select HP Support Assistant. Select HP Support Assistant Quick Start in the top center panel. On the right panel, click Selected Item to expand the section, then select Disable.
What is HP Support Solutions Framework Windows 10?
HP Support Solutions Framework, also short for HPSSF, is a bundled program for many Hewlett-Packard computers and provides a common set of software interfaces, which used to manage and simplify access to the drivers, hardware, and BIOS settings in the operating Microsoft Windows Operating System.
Can I remove HP Sure connect?
Or, you can uninstall HP Sure Connect from your computer by using the Add/Remove Program feature in the Window’s Control Panel. When you find the program HP Sure Connect, click it, and then do one of the following: Windows Vista/7/8: Click Uninstall.
How do I get rid of bloatware on my HP laptop?
We’ll explain step by step how to remove pre-installed programs you don’t need.
- Open Uninstall a program. Open the Windows Start Menu, type ‘control panel’ and open the Control Panel.
- Remove the right bloatware. Here, you can see a list of all the programs on your laptop.
- Restarting your laptop.
What is HP Energy Star?
HP’s ENERGY STAR® qualified products save you money by reducing energy costs and helps protect the environment without sacrificing features or performance. HP is proud to offer our customers products with the ENERGY STAR label.
Pin hp smart
HP Smart Pin
The Smart Pin (Hewlett-Packard Smart Pin) or center pin on power supply connectors most commonly found on Hewlett Packard Laptops and some slimline desktop computers has two implications. The existence of the pin is said to help protect the device by preventing excessive loading. Others in the technology industry believe it is a means to prevent customers from purchasing non-OEM power supplies or adapters for their laptop or desktop computer. They believe the pin is used to identify that a genuine HP adapter is being.
- The outer ring is negative
- The inside wall of the ring is the positive full operating voltage (typically 18v DC)
- The pin is a reduced positive voltage (typically 5v DC or variable)
Hewlett-Packard Company is not forthcoming with detailed information about the Smart Pin. What you will find here is some details based on testing and user data.
HP Pavilion dv7-4276nr Laptop -w- OEM PPP012A-S AC Power Adapter
The AD Power Adapter is PN: 608428-004. This adapter has the center Smart Pin. The adapter is rating +19VDC 1.6A
- The inner ring (2) voltage tests: 19.40 VDC
- The smart pin (3) voltage tests: 18.81 VDC (unloaded)
Unloaded meaning that the volt meter does not provide the completion of a circuit. With the laptop connected, the "load" becomes present, which will reduce voltage across the smart pin. It is presumed that factors such as a charging battery or processor work on the laptop will increase the load, causing further voltage drop on the smart pin.
HP DC7900 USDT Ultra slim Desktop
Modification of Aftermarket Power Adapter
Chinese made aftermarket AC Adapter for HP DC7900 USDT Ultra slim Desktop. This adapter has no standard part number on the unit. The side has a sticker with YALL-2014-10 , S1135 . The main label on the underside reads: Replacement AC Adapter INPUT 100-240V 1.5A 50/60Hz OUTPUT 19V 7.1A
Vendor description: Replacement HP 482133-001 AC Adapter Charger Power Supply Cord
- The inner ring (2) voltage tests: 19.63 VDC
- The smart pin (3) voltage tests: 0 VDC (unloaded)
The vendor claims the adapter will work with this computer. Connecting to the computer, system does not power on. This does not work out-of-the-box.
This is one of many cheap Chinese made imitation products which sometimes work, and sometimes don't, because they do not test compatibility with all models they claim. However, if the adapter produces anywhere in the neighborhood of the correct voltage, and reliability, then it can be modified to work with your HP device. Often, all that is needed is a single 10 cent resistor and your willingness to void the warranty on the new knockoff adapter you just bought. It is much cheaper than buying the HP OEM replacement.
An important consideration in purchasing your AC Adapter is that it will supply sufficient Amps. The amperage rating determines how much laptop or computer it can handle. This guy claims to be a whopping 7.1A which is plenty. It is a large unit which doesn't look like the one pictured in the advertisement.
The smart pin was connected to a transistor. Disconnected from the board and using a 190K Ohm resister between the main positive voltage and the wire to the smart pin. This drops the voltage on the smart pin down near 5-6VDC.
BLUE to WHITE - place the resistor between the blue and white wire.
REMEMBER - The voltage will read much higher than 5 volts when not under a load. A resistor is _not_ a voltage regulator. The loaded voltage drops to 5-6 volts on the center pin when connected to the computer and the computer is operating.
FINALLY - This is the correct relative resistor value for this particular computer system: HP DC7900 USDT Ultra slim Desktop. Other models including HP laptops have different current pulls, they are different loads, and therefore a different resistor value will likely be needed.
AC/DC Adapter Adaptor Transformer Power A/C ACDC
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